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X^2-2.4X=0
a = 1; b = -2.4; c = 0;
Δ = b2-4ac
Δ = -2.42-4·1·0
Δ = 5.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.4)-\sqrt{5.76}}{2*1}=\frac{2.4-\sqrt{5.76}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.4)+\sqrt{5.76}}{2*1}=\frac{2.4+\sqrt{5.76}}{2} $
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